How to get all the 'href' links with the help of using Following siblings in selenium Python

Question

from selenium import webdriver
driver = webdriver.Chrome("C://Users//psingh//AppData//Local//Programs//Python//Python38-32//chromedriver.exe")
driver.get("https://download.cms.gov/nppes/NPI_Files.html")
element = driver.find_element_by_xpath("//tr[./td[./b[text()='Weekly Incremental NPI Files']]]/following-sibling::tr//a")
ele = element.get_attribute("href")
print(ele)
driver.quit()

I want to get all 4 'href' links below 'Weekly Incremental NPI Files' Heading. with above code I am only able to get top 1st link.

Answer 1

Use driver.find_elements_by_xpath elements with an s to get all in element and than loop over the result:

from selenium import webdriver
driver = webdriver.Chrome("C:Program FilesChromeDriverchromedriver.exe")
driver.get("https://download.cms.gov/nppes/NPI_Files.html")
element = driver.find_elements_by_xpath("//tr[./td[./b[text()='Weekly Incremental NPI Files']]]/following-sibling::tr//a")
ele = [ele.get_attribute("href") for ele in element]
print(ele)
driver.quit()